18n^2+15n-63=0

Solution for 18n^2+15n-63=0 equation:

18n^2+15n-63=0

a = 18; b = 15; c = -63;
Δ = b2-4ac
Δ = 152-4·18·(-63)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-69}{2*18}=\frac{-84}{36}
=-2+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+69}{2*18}=\frac{54}{36}
=1+1/2
$